1Why does a nanosecond NIR laser leave a burr on 20 µm copper foil, and a femtosecond source doesn't?
At 1064 nm, copper absorbs the beam within about 13 nm of its surface; only about 4 % of the light is absorbed at all, the rest reflects. The question is what happens to that 4 % in the time the pulse lasts. Copper’s thermal diffusivity is 117 mm²/s, so in one nanosecond heat travels roughly 700 nm — fifty times deeper than the light went. A nanosecond pulse therefore melts a volume far larger than the skin it heated, and material leaves as melt pushed out by vapour pressure. The melt that does not leave freezes as recast and burr, and the heat-affected zone scales with the square root of the pulse duration and the diffusivity.
At 200 fs the same copper moves heat only about 10 nm, less than the optical depth. And 200 fs is shorter than the time electrons take to hand their energy to the lattice, a few picoseconds in most metals. The energy is deposited before conduction can begin, and above a threshold fluence the heated skin leaves as vapour and plasma. In drilling stainless steel, a recast layer of about 25 µm with nanosecond pulses became unmeasurable with picosecond pulses in one published comparison; in electrode-edge work, clearing a 20 µm margin took a 1 ns green source where 250 ns NIR pulses could not hold it.